Your first answers are right.
What is the outlier for the second one?
find the outlier of each set of data describe how the outlier affects the mean. just want to double check on 2 problems that we did
-15
-12
-19
0
-20
-14
the outlier is 0
the mean with the outlier 0
is: -13.33
the mean without the outlier 0
is: -16
is this correct?
next one:
4
-1
-16
2
0
-3
6
-2
for this i added positive got: 12
i added negative and got: -22
do i do 12 - 22
and get 10
10/8 = 1 2/10 = 1 1/5?? not sure on this one
9 answers
the outlier is -16 for question 2
Yes.
-10/8 = -1.2
Eliminating -16, the median is ?
-10/8 = -1.2
Eliminating -16, the median is ?
eliminating -16 would be
12 -6 = 6 for the mean
12 -6 = 6 for the mean
Nope.
eliminating the -16 would be -6
-1
-3
-2
= -6
so 12 - 6 = 6 as mean w/o -16 outlier
-1
-3
-2
= -6
so 12 - 6 = 6 as mean w/o -16 outlier
6/7
,857 is the mean
i messed up
12 + -6 = 6
6 /7
= .857
i forgot a step thanks again and again
.857 is the mean without outlier -16
i messed up
12 + -6 = 6
6 /7
= .857
i forgot a step thanks again and again
.857 is the mean without outlier -16
You're welcome.