Find the numerical equivalent of 4^9 times 4^-7

Question

16
4^16
4
4^2

Answer 1

To solve \( 4^9 \times 4^{-7} \), we can use the property of exponents that states \( a^m \times a^n = a^{m+n} \).

Applying this property:

\[ 4^9 \times 4^{-7} = 4^{9 + (-7)} = 4^{9 - 7} = 4^2 \]

Now we can find the numerical equivalent of \( 4^2 \):

\[ 4^2 = 16 \]

So the answer is:

\[ \boxed{16} \]