Find the numerical equivalent of 3 over 9 ⋅ 3^−5

1 answer

To find the numerical equivalent of \( \frac{3}{9} \cdot 3^{-5} \), we can simplify the expression step by step.

First, simplify \( \frac{3}{9} \):

\[ \frac{3}{9} = \frac{1}{3} \]

Now, substituting this back into the original expression:

\[ \frac{1}{3} \cdot 3^{-5} \]

Next, we can use the property of exponents which states that \( a^{-n} = \frac{1}{a^n} \):

\[ 3^{-5} = \frac{1}{3^5} \]

Thus, our expression becomes:

\[ \frac{1}{3} \cdot \frac{1}{3^5} = \frac{1}{3 \cdot 3^5} \]

Using the property of exponents \( a^m \cdot a^n = a^{m+n} \), we simplify the denominator:

\[ 3 \cdot 3^5 = 3^{1+5} = 3^6 \]

So we have:

\[ \frac{1}{3^6} \]

To find the numerical value of \( 3^6 \):

\[ 3^6 = 729 \]

Therefore,

\[ \frac{1}{3^6} = \frac{1}{729} \]

The numerical equivalent of the original expression \( \frac{3}{9} \cdot 3^{-5} \) is

\[ \boxed{\frac{1}{729}} \]