find the numerical equivalent of 2 to the power of 5 . 2 to the power of -2

Question

2
8
16
128

Answer 1

To solve the expression \(2^5 \cdot 2^{-2}\), we can use the property of exponents which states that \(a^m \cdot a^n = a^{m+n}\).

So, we can combine the powers:

\[ 2^5 \cdot 2^{-2} = 2^{5 + (-2)} = 2^{5 - 2} = 2^3 \]

Now, we calculate \(2^3\):

\[ 2^3 = 2 \cdot 2 \cdot 2 = 8 \]

So, the numerical equivalent of \(2^5 \cdot 2^{-2}\) is 8.