Find the numerical equivalent of 2^5 ⋅2^−2 (1 point)

Question

Responses

2
2

8
8

128
128

16

Answer 1

To find the numerical equivalent of \( 2^5 \cdot 2^{-2} \), we can use the property of exponents that states \( a^m \cdot a^n = a^{m+n} \).

In this case:

\[ 2^5 \cdot 2^{-2} = 2^{5 + (-2)} = 2^{5 - 2} = 2^3 \]

Now, we calculate \( 2^3 \):

\[ 2^3 = 8 \]

So, the numerical equivalent of \( 2^5 \cdot 2^{-2} \) is \( 8 \).

Thus, the correct response is:

8