Find the numerical equivalent of 2^5 ⋅2^−2

Question

(1 point)
Responses

16
16

128
128

2
2

8

Answer 1

To find the numerical equivalent of \( 2^5 \cdot 2^{-2} \), we can use the property of exponents that states \( a^m \cdot a^n = a^{m+n} \).

So,

\[ 2^5 \cdot 2^{-2} = 2^{5 + (-2)} = 2^{5 - 2} = 2^3 \]

Now, calculating \( 2^3 \):

\[ 2^3 = 8 \]

Therefore, the numerical equivalent of \( 2^5 \cdot 2^{-2} \) is 8.