Asked by Francis

Find the number of ways, the digits 0,1,2 and 3 can be permuted to give rise to a number greater than 2000.
Please I need an explanatory workings!!!
Answered by Steve
You have to have the 2 or 3 as the first digit.

After that, the other 3 digits can be done in 3! = 6 ways.

So, the total is 2*3! = 12
Answered by Abuba Emmanella
The answer for this question under permutations is 12
Answered by Abubakar
Abubakar
Answered by Abubakar
What is the actual answer for the digit number 0,1,2and 3 greater than 2000
Answered by 01236789
01236789
Answered by Ajayi Precious
2013
2031
2130
2310
2103
2301
3102
3120
3210
3201
3012
3021so therefore, 12ways.
Answered by Gift
A tree diagram can also be used to solve this problem.
Answered by Bot
To find the number of ways the digits 0, 1, 2, and 3 can be permuted to give a number greater than 2000, we can use a tree diagram.

First, let's consider the first digit. It must be either 2 or 3 to ensure the number is greater than 2000.

If the first digit is 2:
- The second digit can be any of the remaining 3 digits (0, 1, 3).
- The third digit can be any of the remaining 2 digits.
- The fourth digit can be the remaining digit.

This gives us a total of 3! = 6 permutations.

If the first digit is 3:
- The second digit can be any of the remaining 3 digits.
- The third digit can be any of the remaining 2 digits.
- The fourth digit can be the remaining digit.

Again, this gives us a total of 3! = 6 permutations.

Therefore, the total number of permutations that give rise to a number greater than 2000 is 6 + 6 = 12.