Find the number of solutions to
x_1 + x_2 + x_3 + x_4 + x_5 + x_6 + x_7 + x_8 + x_9 + x_10 <= 2
in nonnegagive integers.
2 answers
2,048
AAAaannndd the bot gets it wrong yet again!
If one of the numbers is 2, then the other 9 are all zeros, so 10 ways
If two of the numbers are 1, then 10C2=45 ways.
So, 55 ways in all
If one of the numbers is 2, then the other 9 are all zeros, so 10 ways
If two of the numbers are 1, then 10C2=45 ways.
So, 55 ways in all