θ = s/r = (6 m)/(5/2 m) = 12/5 radians = 2.4 radians
r = s/θ = (60 ft)/(3π/2) = 40/π ft ≅ 12.732 ft
find the number of radians in the central angle that subtends an arc of 6m on a circle of diameter 5m
2 answers
θ = s/r = (6 m)/(5/2 m)
(6/1)(2/5)= 12/5 (2.4)
= 2.4 radians
(6/1)(2/5)= 12/5 (2.4)
= 2.4 radians