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Find the nth term and first three terms of the arithmetic squence having U4=93 and U8=65?

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U8-U4 = 4d, so d = (65-93)/4 = -7
U1 = U4 - 3d = 93+21 = 114
Un = 114 + (n-1)(-7) = 121 - 7n

What about the substitution method

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