To find the molarity of the solution, we first need to calculate the number of moles of NaNO3 in the solution.
Given:
Mass of NaNO3 = 25.0 g
Volume of solution = 350 mL = 0.350 L
First, calculate the number of moles of NaNO3:
Molar mass of NaNO3 = 85.0 g/mol
Number of moles = Mass / Molar mass
= 25.0 g / 85.0 g/mol
≈ 0.294 moles
Now, calculate the molarity of the solution:
Molarity (M) = Number of moles / Volume of solution (in liters)
= 0.294 moles / 0.350 L
≈ 0.84 M
Therefore, the molarity of the solution prepared by dissolving 25.0 g of NaNO3 into enough water to make 350 mL of solution is approximately 0.84 M.
Find the molarity of a solution prepared by dissolving 25.0 of NaNO3 into enough water to make 350 mL of solution
1 answer