Find the molarity of a solution prepared by dissolving 25.0 of NaNO3 into enough water to make 350 mL of solution

Answer 1

To find the molarity of the solution, we first need to calculate the number of moles of NaNO3 in the solution.

Given:
Mass of NaNO3 = 25.0 g
Volume of solution = 350 mL = 0.350 L

First, calculate the number of moles of NaNO3:
Molar mass of NaNO3 = 85.0 g/mol

Number of moles = Mass / Molar mass
= 25.0 g / 85.0 g/mol
≈ 0.294 moles

Now, calculate the molarity of the solution:
Molarity (M) = Number of moles / Volume of solution (in liters)
= 0.294 moles / 0.350 L
≈ 0.84 M

Therefore, the molarity of the solution prepared by dissolving 25.0 g of NaNO3 into enough water to make 350 mL of solution is approximately 0.84 M.