Find the molar it’s of a solution prepared by dissolving 25.0 of NaNO3 into enough water to make 350 mL of solution

Answer 1

To find the molarity of the solution, we first need to calculate the number of moles of NaNO3 in the solution.

Step 1: Calculate the number of moles of NaNO3
Molar mass of NaNO3 = 22.99 (Na) + 14.01 (N) + 3(16.00) (O) = 85.00 g/mol

Number of moles = mass / molar mass
Number of moles = 25.0 g / 85.00 g/mol = 0.294 moles

Step 2: Calculate the volume of the solution in liters
Volume = 350 mL = 350/1000 L = 0.350 L

Step 3: Calculate the molarity of the solution
Molarity (M) = Number of moles / Volume
Molarity = 0.294 moles / 0.350 L = 0.84 M

Therefore, the molarity of the solution prepared by dissolving 25.0 g of NaNO3 into enough water to make 350 mL of solution is 0.84 M.