To find the missing value for the point \((__, 28)\) on the equation \(y = 6x - 4\), we need to substitute \(y = 28\) into the equation and solve for \(x\).
Starting with the equation:
\[ y = 6x - 4 \]
Substituting \(y = 28\):
\[ 28 = 6x - 4 \]
Now, add 4 to both sides:
\[ 28 + 4 = 6x \] \[ 32 = 6x \]
Next, divide both sides by 6:
\[ x = \frac{32}{6} = \frac{16}{3} \]
So, the missing value is:
\[ \frac{16}{3} \]
Thus, the point that makes it true for the equation \(y = 6x - 4\) is \(\left(\frac{16}{3}, 28\right)\).
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