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Find the missing side lengths, perimeter, and area of triangle ABC on the coordinate plane. All answers should be in simplest r...Question
Find the missing side lengths, perimeter, and area of triangle ABC on the coordinate plane. All answers should be in simplest radical form, if necessary: (5 points) Put responses in the correct input to answer the question. Select a response, navigate to the desired input and insert the response. Responses can be selected and inserted using the space bar, enter key, left mouse button or touchpad. Responses can also be moved by dragging with a mouse. Side Length AB: Response area Side Length BC: Response area Side Length AC: Response area Perimeter of Triangle ABC: Response area Area of Triangle ABC: Response area Note: the formula for area of a triangle is A=bh2 , where b is the length of the base (BC) and h is the height from side BC to point A. Skip to navigation
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Answered by
GPT-4o mini
To find the missing side lengths, perimeter, and area of triangle ABC on the coordinate plane, we need the coordinates of the vertices A, B, and C.
For example, let's say you have the following coordinates for the vertices:
- A(0, 0)
- B(4, 0)
- C(2, 3)
### Step 1: Calculate the Lengths of the Sides
1. **Length AB:**
\[
AB = \sqrt{(4 - 0)^2 + (0 - 0)^2} = \sqrt{16} = 4
\]
2. **Length BC:**
\[
BC = \sqrt{(2 - 4)^2 + (3 - 0)^2} = \sqrt{4 + 9} = \sqrt{13}
\]
3. **Length AC:**
\[
AC = \sqrt{(2 - 0)^2 + (3 - 0)^2} = \sqrt{4 + 9} = \sqrt{13}
\]
### Step 2: Calculate the Perimeter
\[
\text{Perimeter} = AB + BC + AC = 4 + \sqrt{13} + \sqrt{13} = 4 + 2\sqrt{13}
\]
### Step 3: Calculate the Area
Using the formula for the area of a triangle, where \( b \) is the length of side BC and \( h \) is the height from point A to line BC:
\[
A = \frac{bh}{2}
\]
The base \( BC = \sqrt{13} \) and the height from A(0, 0) is the y-coordinate of point C(2, 3), which is 3:
\[
\text{Area} = \frac{\sqrt{13} \cdot 3}{2} = \frac{3\sqrt{13}}{2}
\]
### Final Answers
- Side Length AB: **4**
- Side Length BC: **\(\sqrt{13}\)**
- Side Length AC: **\(\sqrt{13}\)**
- Perimeter of Triangle ABC: **\(4 + 2\sqrt{13}\)**
- Area of Triangle ABC: **\(\frac{3\sqrt{13}}{2}\)**
Make sure to use the correct coordinates and calculations based on your specific triangle ABC if they differ from the example provided.
For example, let's say you have the following coordinates for the vertices:
- A(0, 0)
- B(4, 0)
- C(2, 3)
### Step 1: Calculate the Lengths of the Sides
1. **Length AB:**
\[
AB = \sqrt{(4 - 0)^2 + (0 - 0)^2} = \sqrt{16} = 4
\]
2. **Length BC:**
\[
BC = \sqrt{(2 - 4)^2 + (3 - 0)^2} = \sqrt{4 + 9} = \sqrt{13}
\]
3. **Length AC:**
\[
AC = \sqrt{(2 - 0)^2 + (3 - 0)^2} = \sqrt{4 + 9} = \sqrt{13}
\]
### Step 2: Calculate the Perimeter
\[
\text{Perimeter} = AB + BC + AC = 4 + \sqrt{13} + \sqrt{13} = 4 + 2\sqrt{13}
\]
### Step 3: Calculate the Area
Using the formula for the area of a triangle, where \( b \) is the length of side BC and \( h \) is the height from point A to line BC:
\[
A = \frac{bh}{2}
\]
The base \( BC = \sqrt{13} \) and the height from A(0, 0) is the y-coordinate of point C(2, 3), which is 3:
\[
\text{Area} = \frac{\sqrt{13} \cdot 3}{2} = \frac{3\sqrt{13}}{2}
\]
### Final Answers
- Side Length AB: **4**
- Side Length BC: **\(\sqrt{13}\)**
- Side Length AC: **\(\sqrt{13}\)**
- Perimeter of Triangle ABC: **\(4 + 2\sqrt{13}\)**
- Area of Triangle ABC: **\(\frac{3\sqrt{13}}{2}\)**
Make sure to use the correct coordinates and calculations based on your specific triangle ABC if they differ from the example provided.
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