Find the minimum or maximum value of f(x)=−0.25x2+4x−18

Answer 1

recall that the vertex of the parabola

ax^2+bx+c

is at x = -b/2a

So, your maximum is at x = 4/.5 = 8

now just find f(8)

Answer 2

Sow steps for 5x - 3y equals 0 to determine if this is a direct variation

Answer 3

Show steps for 5x - 3y equals 0 to determine if this is a direct variation

Answer 4

Find the minimum or maximum value of f(x)=−0.25x2+4x−18.

Answer 5

This was wrong