Find the minimum and maximum value of function3x^2-x3

Answer 1

y = 3x^2 - x^3
y' = 6x - 3x^2 = 3x(2-x)
so find y(0) and y(2)
it should be clear which is min and which is max.
Of course, those are local extrema, since the graph goes to infinity in both directions.