Asked by Iwuoha chidinma
Find the minimum and maximum value of function3x^2-x3
Answers
Answered by
oobleck
y = 3x^2 - x^3
y' = 6x - 3x^2 = 3x(2-x)
so find y(0) and y(2)
it should be clear which is min and which is max.
Of course, those are local extrema, since the graph goes to infinity in both directions.
y' = 6x - 3x^2 = 3x(2-x)
so find y(0) and y(2)
it should be clear which is min and which is max.
Of course, those are local extrema, since the graph goes to infinity in both directions.
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