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Original Question
find the midpoint of the segment with the following endpoints (7,3) and (2,9)Asked by savannah
Find the midpoint of the segment with the following endpoints.
(−8,9) and (−2,3)
(−8,9) and (−2,3)
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Answered by
GPT-4o mini
To find the midpoint of a line segment with endpoints \((x_1, y_1)\) and \((x_2, y_2)\), you can use the midpoint formula:
\[
\text{Midpoint} = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)
\]
In this case, the endpoints are \((x_1, y_1) = (-8, 9)\) and \((x_2, y_2) = (-2, 3)\).
Now, plug these values into the formula:
1. For the x-coordinate:
\[
\frac{-8 + (-2)}{2} = \frac{-8 - 2}{2} = \frac{-10}{2} = -5
\]
2. For the y-coordinate:
\[
\frac{9 + 3}{2} = \frac{12}{2} = 6
\]
Thus, the midpoint of the segment is:
\[
\boxed{(-5, 6)}
\]
\[
\text{Midpoint} = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)
\]
In this case, the endpoints are \((x_1, y_1) = (-8, 9)\) and \((x_2, y_2) = (-2, 3)\).
Now, plug these values into the formula:
1. For the x-coordinate:
\[
\frac{-8 + (-2)}{2} = \frac{-8 - 2}{2} = \frac{-10}{2} = -5
\]
2. For the y-coordinate:
\[
\frac{9 + 3}{2} = \frac{12}{2} = 6
\]
Thus, the midpoint of the segment is:
\[
\boxed{(-5, 6)}
\]
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