To find the median, we need to first put the numbers in order:
4, 5, 27, 44
The median is the middle number, which in this case is 16, since it is halfway between 5 and 27.
To find the mean, we add up all the numbers and divide by how many there are:
(44 + 4 + 27 + 5) / 4 = 20
So the mean is 20.
Find the median and mean of the data set below:
44,4,27,5
11 answers
Find the median and mean of the data set below:
19,44,16,26,12
19,44,16,26,12
To find the median, we first need to order the numbers from lowest to highest:
12, 16, 19, 26, 44
The median is the middle number, which in this case is 19.
To find the mean, we add up all the numbers and divide by how many there are:
(19 + 44 + 16 + 26 + 12) / 5 = 23.4
So the mean is 23.4.
12, 16, 19, 26, 44
The median is the middle number, which in this case is 19.
To find the mean, we add up all the numbers and divide by how many there are:
(19 + 44 + 16 + 26 + 12) / 5 = 23.4
So the mean is 23.4.
The table displays the scores of students on a recent exam. Find the mean of the scores to the nearest 10th.
Score Number of Students
75 9
80 6
85 8
90 2
95 4
100 6
Score Number of Students
75 9
80 6
85 8
90 2
95 4
100 6
We can find the mean by multiplying each score by the number of students who received that score, adding up those products, and then dividing by the total number of students:
(75 x 9) + (80 x 6) + (85 x 8) + (90 x 2) + (95 x 4) + (100 x 6) = 4060
There were 35 students who took the exam, so:
4060 / 35 = 116
Rounding this to the nearest tenth, the mean score is 116.0.
(75 x 9) + (80 x 6) + (85 x 8) + (90 x 2) + (95 x 4) + (100 x 6) = 4060
There were 35 students who took the exam, so:
4060 / 35 = 116
Rounding this to the nearest tenth, the mean score is 116.0.
The 8 students in the Environmental Club represent 2% of the students in the seventh grade. How many students are in the seventh grade?
If 8 students represent 2% of the seventh grade, we can set up a proportion to find the total number of students:
8/x = 2/100
To solve for x, we can cross-multiply:
2x = 800
Dividing both sides by 2, we get:
x = 400
Therefore, there are 400 students in the seventh grade.
8/x = 2/100
To solve for x, we can cross-multiply:
2x = 800
Dividing both sides by 2, we get:
x = 400
Therefore, there are 400 students in the seventh grade.
Bob's gift shop sold a record number of cards for Mother's Day. One salesman sold 20 cards, which was 25% of the cards sold for Mother's Day. How many cards were sold for Mother's Day?
Let's call the total number of cards sold for Mother's Day "x".
According to the problem, one salesman sold 25% of the cards, or 0.25x. We also know that the number of cards this salesman sold was 20.
So we can set up an equation:
0.25x = 20
To solve for x, we can divide both sides by 0.25:
x = 80
Therefore, a total of 80 cards were sold for Mother's Day.
According to the problem, one salesman sold 25% of the cards, or 0.25x. We also know that the number of cards this salesman sold was 20.
So we can set up an equation:
0.25x = 20
To solve for x, we can divide both sides by 0.25:
x = 80
Therefore, a total of 80 cards were sold for Mother's Day.
The table displays the scores of students on a recent exam. Find the mean of the scores to the nearest 10th.
Score Number of Students
70
70
6
6
75
75
3
3
80
80
9
9
85
85
5
5
90
90
7
7
95
95
8
8
Score Number of Students
70
70
6
6
75
75
3
3
80
80
9
9
85
85
5
5
90
90
7
7
95
95
8
8
We need to find the sum of all the scores, and divide by the total number of students:
(70 x 2) + (75 x 2) + (80 x 2) + (85 x 2) + (90 x 2) + (95 x 2) = 1300
There were 30 students who took the exam, so:
1300 / 30 = 43.33
Rounding this to the nearest tenth, the mean score is 43.3.
(70 x 2) + (75 x 2) + (80 x 2) + (85 x 2) + (90 x 2) + (95 x 2) = 1300
There were 30 students who took the exam, so:
1300 / 30 = 43.33
Rounding this to the nearest tenth, the mean score is 43.3.