Mean = (15+25+35+45+55+65)/6 = 40
Deviation = (15-40) + (25-40) + (35-40) + (45-40) + (55-40) + (65-40)
= -25 + -15 + -5 + 5 + 15 + 25
= 0
Mean Deviation about the Mean = 0
Find the mean deviation about the mean of the following data of ages of married men in a certain town.
Ages 15-24:25-34 35-44 45-54 55-64 65-74
No. of Men 33 264 303 214 128 58
2 answers
Find the mean deviation about the mean of the following data of ages of married men in a certain town.
Ages 15-24 25-34 35-44 45-54 55-64 65-74
No. of Men 33 264 303 214 128 58
Ages 15-24 25-34 35-44 45-54 55-64 65-74
No. of Men 33 264 303 214 128 58