Find the mean deviation about the mean of the following data of ages of married men in a certain town.

Ages 15-24:25-34 35-44 45-54 55-64 65-74

No. of Men 33 264 303 214 128 58

2 answers

Mean = (33*15 + 264*25 + 303*35 + 214*45 + 128*55 + 58*65)/(33 + 264 + 303 + 214 + 128 + 58)

Mean = 39.7

Mean Deviation about the Mean = (33*|15-39.7| + 264*|25-39.7| + 303*|35-39.7| + 214*|45-39.7| + 128*|55-39.7| + 58*|65-39.7|)/(33 + 264 + 303 + 214 + 128 + 58)

Mean Deviation about the Mean = 17.7
Mean = (33*15 + 264*25 + 303*35 + 214*45 + 128*55 + 58*65)/(33 + 264 + 303 + 214 + 128 + 58)

Mean = 39.7

Mean Deviation about the Mean = (33*|15-39.7| + 264*|25-39.7| + 303*|35-39.7| + 214*|45-39.7| + 128*|55-39.7| + 58*|65-39.7|)/(33 + 264 + 303 + 214 + 128 + 58)

Mean Deviation about the Mean = 17.7