First, calculate the mean of the dataset:
(8.4 + 9.4 + 14.2 + 5.6 + 8.3 + 9.0 + 10.2) / 7 = 9.4
Next, calculate the absolute deviations from the mean for each number in the dataset:
|8.4 - 9.4| = 1.0
|9.4 - 9.4| = 0.0
|14.2 - 9.4| = 4.8
|5.6 - 9.4| = 3.8
|8.3 - 9.4| = 1.1
|9.0 - 9.4| = 0.4
|10.2 - 9.4| = 0.8
Now, calculate the mean absolute deviation by finding the mean of these absolute deviations:
(1.0 + 0.0 + 4.8 + 3.8 + 1.1 + 0.4 + 0.8) / 7 = 1.8
Therefore, the mean absolute deviation of the dataset is 1.8.
Find the mean absolute deviation of the following dataset: 8.4, 9.4, 14.2, 5.6, 8.3, 9.0, 10.2. Round the answer to the nearest tenth.(1 point)
7 answers
wrong
Apologies for the error. Let's recalculate the mean absolute deviation of the dataset.
First, calculate the mean of the dataset:
(8.4 + 9.4 + 14.2 + 5.6 + 8.3 + 9.0 + 10.2) / 7 = 8.8
Next, calculate the absolute deviations from the mean for each number in the dataset:
|8.4 - 8.8| = 0.4
|9.4 - 8.8| = 0.6
|14.2 - 8.8| = 5.4
|5.6 - 8.8| = 3.2
|8.3 - 8.8| = 0.5
|9.0 - 8.8| = 0.2
|10.2 - 8.8| = 1.4
Now, calculate the mean absolute deviation by finding the mean of these absolute deviations:
(0.4 + 0.6 + 5.4 + 3.2 + 0.5 + 0.2 + 1.4) / 7 ≈ 1.9
Therefore, rounding to the nearest tenth, the mean absolute deviation of the dataset is approximately 1.9.
First, calculate the mean of the dataset:
(8.4 + 9.4 + 14.2 + 5.6 + 8.3 + 9.0 + 10.2) / 7 = 8.8
Next, calculate the absolute deviations from the mean for each number in the dataset:
|8.4 - 8.8| = 0.4
|9.4 - 8.8| = 0.6
|14.2 - 8.8| = 5.4
|5.6 - 8.8| = 3.2
|8.3 - 8.8| = 0.5
|9.0 - 8.8| = 0.2
|10.2 - 8.8| = 1.4
Now, calculate the mean absolute deviation by finding the mean of these absolute deviations:
(0.4 + 0.6 + 5.4 + 3.2 + 0.5 + 0.2 + 1.4) / 7 ≈ 1.9
Therefore, rounding to the nearest tenth, the mean absolute deviation of the dataset is approximately 1.9.
also wrong
correct
First, calculate the mean of the dataset:
(8.4 + 9.4 + 14.2 + 5.6 + 8.3 + 9.0 + 10.2) / 7 = 9.4
Next, calculate the absolute deviations from the mean for each number in the dataset:
|8.4 - 9.4| = 1.0
|9.4 - 9.4| = 0.0
|14.2 - 9.4| = 4.8
|5.6 - 9.4| = 3.8
|8.3 - 9.4| = 1.1
|9.0 - 9.4| = 0.4
|10.2 - 9.4| = 0.8
Now, calculate the mean absolute deviation by finding the mean of these absolute deviations:
(1.0 + 0.0 + 4.8 + 3.8 + 1.1 + 0.4 + 0.8) / 7 = 1.8
Therefore, the mean absolute deviation of the dataset is 1.8.
(8.4 + 9.4 + 14.2 + 5.6 + 8.3 + 9.0 + 10.2) / 7 = 9.4
Next, calculate the absolute deviations from the mean for each number in the dataset:
|8.4 - 9.4| = 1.0
|9.4 - 9.4| = 0.0
|14.2 - 9.4| = 4.8
|5.6 - 9.4| = 3.8
|8.3 - 9.4| = 1.1
|9.0 - 9.4| = 0.4
|10.2 - 9.4| = 0.8
Now, calculate the mean absolute deviation by finding the mean of these absolute deviations:
(1.0 + 0.0 + 4.8 + 3.8 + 1.1 + 0.4 + 0.8) / 7 = 1.8
Therefore, the mean absolute deviation of the dataset is 1.8.
I meant
Apologies for the error. Let's recalculate the mean absolute deviation of the dataset.
First, calculate the mean of the dataset:
(8.4 + 9.4 + 14.2 + 5.6 + 8.3 + 9.0 + 10.2) / 7 = 8.8
Next, calculate the absolute deviations from the mean for each number in the dataset:
|8.4 - 8.8| = 0.4
|9.4 - 8.8| = 0.6
|14.2 - 8.8| = 5.4
|5.6 - 8.8| = 3.2
|8.3 - 8.8| = 0.5
|9.0 - 8.8| = 0.2
|10.2 - 8.8| = 1.4
Now, calculate the mean absolute deviation by finding the mean of these absolute deviations:
(0.4 + 0.6 + 5.4 + 3.2 + 0.5 + 0.2 + 1.4) / 7 ≈ 1.9
Therefore, rounding to the nearest tenth, the mean absolute deviation of the dataset is approximately 1.9.
Apologies for the error. Let's recalculate the mean absolute deviation of the dataset.
First, calculate the mean of the dataset:
(8.4 + 9.4 + 14.2 + 5.6 + 8.3 + 9.0 + 10.2) / 7 = 8.8
Next, calculate the absolute deviations from the mean for each number in the dataset:
|8.4 - 8.8| = 0.4
|9.4 - 8.8| = 0.6
|14.2 - 8.8| = 5.4
|5.6 - 8.8| = 3.2
|8.3 - 8.8| = 0.5
|9.0 - 8.8| = 0.2
|10.2 - 8.8| = 1.4
Now, calculate the mean absolute deviation by finding the mean of these absolute deviations:
(0.4 + 0.6 + 5.4 + 3.2 + 0.5 + 0.2 + 1.4) / 7 ≈ 1.9
Therefore, rounding to the nearest tenth, the mean absolute deviation of the dataset is approximately 1.9.