Don't forget your Algebra I now that you're taking precal
R(x) = x(352 - 0.6x)
The maximum occurs midway between the roots, at x = 293.33
So just find R(293.33) = 51626.67
Find the maximum revenue for the revenue function
R(x) = 352x − 0.6x2.
(Round your answer to the nearest cent.)
1 answer