find the mass of silver chloride formed from 33.2ml of a 0.100M solution of silver nitrate and 200ml of 0.200M solution of calcium chloride solution

Solution
plan:use mass to mass calculations
mass of AgNO3-moles of AgNO3-moles of AgCl-mass of AgCl
0.1mol/1L*0.0332L+0.200mol/1L=0.04332mol(moles of calcium and moles of silver nitrate)
0.04332moles*2molesAgCl/(1moleCaCl2*2molAg(NO3)2)=0.04332moles Agcl
0.04332molsAgCl*143.45g/1mole
=6.211g of AgCl