not quite
v= 8(cos135 degrees i + sin135 degrees J)
= 8(-1/√2, 1/√2)
the magnitude of (-1/√2, 1/√2) is 1
so the magnitude of 8(-1/√2, 1/√2) is 8
Your direction is correct
Find the magnitude and direction angle of the vector v.
v= 8(cos135 degrees i + sin135 degrees J)
I think that the answer is v= 5 and Q = 135. Am I correct?
2 answers
Thank You!!