The magnitude of vector u is given by the formula:
|u| = sqrt(9^2 + (-2)^2) = sqrt(81 + 4) = sqrt(85) ≈ 9.2
The direction angle θ of vector u is given by the formula:
θ = arctan(-2/9)
Using a calculator, we find arctan(-2/9) ≈ -0.218 radians ≈ -12.5 degrees
Therefore, the magnitude of vector u is approximately 9.2 and the direction angle θ is approximately -12.5 degrees.
Find the magnitude and direction angle θ of the following vectors. Round the magnitude to the nearest tenth, and round the direction angle to the nearest degree, if rounding is necessary.
u = (9, -2)
1 answer