|v| = √(5√2)^2 + (5√2)^2) = √(50+50) = 10
tanθ = y/x = -5√2 / 5√2 = -1
θ = -45°
Plot the point and you can easily see that this is so.
Find the magnitude and direction angle for each vector. Give the measure of the direction angle as an angle in [0,360].
<5sqrt2,-5sqrt2>
1 answer