Asked by Anon
Find the local maximum and minimum values of f, using both the First and the Second Derivative Tests
f(x) = x^2/x - 1
f(x) = x^2/x - 1
Answers
Answered by
oobleck
I assume you mean
f(x) = x^2/(x-1)
f'(x) = x(x-2)/(x-1)^2
so f'=0 at x=0,2 and the local extrema are at (0,0) and(2,4)
f"(x) = 2/(x-1)^3
f"(0) = -2 < 0 so (0,0) is a max
f"(2) = 2 > 0 so (2,4) is a min
now be sure to read the question carefully
f(x) = x^2/(x-1)
f'(x) = x(x-2)/(x-1)^2
so f'=0 at x=0,2 and the local extrema are at (0,0) and(2,4)
f"(x) = 2/(x-1)^3
f"(0) = -2 < 0 so (0,0) is a max
f"(2) = 2 > 0 so (2,4) is a min
now be sure to read the question carefully
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.