Ask a New Question

find the limit without using L'Hopital's Rule

Lim(X->-4) (16-x^2 / x+4)

1 answer

No need for L'Hopital
16-x^2 = (4-x)(4+x)

so you really have:
(4-x) at x = -4
4-(-4) = 8

Ask a New Question or answer this question.

Similar Questions

Using l'hopital's rule, find the limit as x approaches zero of(e^(6/x)-6x)^(X/2) I know l'hopital's rule, but this is seeming to
1. 3 answers
Using l'hopital's rule, find the limit as x approaches infinity of(e^(6/x)-6x)^(X/2) I know l'hopital's rule, but this is
1. 0 answers
Use L’Hopital’s rule to find the limit of this sequence(n^100)/(e^n) ...If you do L'Hop. Rule it would take forever, right?
1. 0 answers
Use L’Hopital’s rule to find the limit of this sequence(n^100)/(e^n) ...If you do L'Hop. Rule it would take forever, right?
1. 2 answers

more similar questions