Find the limit. Use l'Hospital's Rule if appropriate. If there is a more elementary method, consider using it.

lim x→3 (x^2+3x−18)/(x−3)

1 answer

how about I do this one, and you at least try on the others?

x^2+3x-18 = (x+6)(x-3)

So, everywhere except at x=3, f(x) = x+6
That means we expect the limit to be 3+6=9

Using the suggestion, the limit is

(2x+3)/1 = 2*6+3 = 9