Find the limit of f(x) as x approaches 0.

f(x) = [1-cos^2(3x)] / x^2

Is there a way to do this if we haven't learned L'Hopital's rule yet?
Can we rewrite 1-cos^2(3x) as sin^2(3x), and then use the basic limit: lim x→0 sin(x) / x = 1?

Thank you!

1 answer

that's the way I'd do it.

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