Find the limit. lim t-->∞ [(t^2 -t)/(t-1)I +√((t+8))j + sin(πt)/ln(t)k]

Answer 1

huh.
clearly, (t^2-t)/(t-1) = t and goes to ∞
likewise, √(t+8) -> ∞
since ln(t) -> ∞ and |sin(πt)| <= 1, the quotient -> 0