find the limit:

Lim (49x^2-25)/(7x-5)
x->5/7

2 answers

since 79x^2 - 25 = (7x-5)(7x+5)

f(x) = 7x+5 for x ≠ 5/7

so, the limit is 7(5/7) + 5 = 10
thank u