since 79x^2 - 25 = (7x-5)(7x+5)
f(x) = 7x+5 for x ≠ 5/7
so, the limit is 7(5/7) + 5 = 10
find the limit:
Lim (49x^2-25)/(7x-5)
x->5/7
2 answers
thank u
Lim (49x^2-25)/(7x-5)
x->5/7
2 answers