by Pythagoras ... x^2 + (x + 3)^2 = (x + 6)^2
2x^2 + 6x + 9 = x^2 + 12x + 36
x^2 - 6x - 27 = 0 ... (x + 3)(x - 9) = 0
Find the lengths of each side give the following right triangle:
Base=x
hypotenuse=x+6
last side=x+3
thank you!
1 answer