find the length width and area of an object where the perimeter is fixed at 20 meters
4 answers
What kind of object?
a rectangle
P = 2L + 2W
30 = 2(5) + 2(5)
or
20 = 2(4) + 2(6)
or
20 = 2(3) + 2(7)
or
20 = 2(2) + 2(8)
or
20 = 2(1) + 2(9)
30 = 2(5) + 2(5)
or
20 = 2(4) + 2(6)
or
20 = 2(3) + 2(7)
or
20 = 2(2) + 2(8)
or
20 = 2(1) + 2(9)
Correction:
the first combination should be:
20 = 2(5) + 2(5)
the first combination should be:
20 = 2(5) + 2(5)