(-2, 4) --> (x1, y1)
(3, 6) --> (x2, y2)
Using the distance of a line formula (derived from the Pythagorean Theorem):
d = sqrt[(x2-x1)² + (y2-y1)²]
d = sqrt[(3-(-2))² + (6-4)²]
d = sqrt[(3+2)² + (6-4)²]
d = sqrt[(5)² + (2)²]
d = sqrt[25 + 4]
∴d = sqrt(29) ≈ 5.39 units
Find the length of the line segment joining the points (−2, 4) and (3, 6)
2 answers
Ok I got it