CD is just the hypotenuse of a right triangle. Its length is
√((5+3)^2+(6-1)^2)
The midpoint's coordinates are just the average of the ends:
((-6+8)/2,(4-2)/2)
slope is just ∆y/∆x, or
(1+3)/(1+2)
Find the length of a line segment ---
CD with endpoint C at (-3, 1) ad endpoint D at (5, 6). round your answer to the nearest tenth, if necessary.
A. 9.4
B. 5.4
C. 3.6 ]
D. 11.7
Find the midpoint of a segment FG with point F at (-6, 4) and midpoint G at (8, -2)
A. (-7, 3)
B. (7, -3)
C. (1, 1)
D. (-1, -1)
Find the slope of a line that passes through (-2, -3) and (1, 1)
A. 1/1
B. 1
C. 2
D. 4/3
3 answers
but what is the answer Steve? thats PLEASE HELPS question
C'mon, guy, you gonna do any of the work? I gave you the numbers -- can't you at least do the evaluation?
√((5+3)^2+(6-1)^2) = √(8^2+5^2) = √(64+25) = √89 = 9.4
So, (A)
Now you try the others.
√((5+3)^2+(6-1)^2) = √(8^2+5^2) = √(64+25) = √89 = 9.4
So, (A)
Now you try the others.