For simple pendulum
T =2•π•sqrt(L/g)
FIND THE LENGTH (IN CM) OF A PENDULUM WITH A PERIOD OF 1.20S.
4 answers
I ended up with 35.746cm. Is that correct?
1.2 = 2 pi sqrt (L/g)
.0365 = L/ 9.8
L = .357 m
= 35.7 cm yes
.0365 = L/ 9.8
L = .357 m
= 35.7 cm yes
Yes. 0.357 m or 35.7 cm