Find the lateral area of a regular hexagonal pyramid with base edge of 10 in and lateral edge of 13 in.

Answer 1

you can find the height of each triangle ...
h^2 + 5^2 = 13^2
h = 12
Area of one such triangle = (1/2)base x heigh = (1/2)(10)(12) = 60

there will be 6 such triangles

You don't say if you include the base in the surface area, if so ...
then you can find the area of one of the six equilateral triangles that form the base.

Answer 2

1/2 PL

P=10*6 because all sides of the hexagon r 10

L=9

60*9/2

270