3^m + 2^n
powers of 2: 2,4,8,16,32,64,128,256,512
powers of 3: 3,9,27,81,243,729
729+256 = 985
243+512 = 755
Looks like 985 is the winner
Find the largest three-digit number that can be written in the form $3^m + 2^n$, where $m$ and $n$ are positive integers.
1 answer
2 answers