Find the largest possible real value of
\sqrt{(x-20)(y-x)} + \sqrt{(140-y)(20-x)} + \sqrt{(x-y)(y-140)}
subject to -40\leq x \leq 100 and -20\leq y \leq 200.
2 answers
80?
432.5
\sqrt{(x-20)(y-x)} + \sqrt{(140-y)(20-x)} + \sqrt{(x-y)(y-140)}
subject to -40\leq x \leq 100 and -20\leq y \leq 200.
2 answers
1 answer
7 answers
1 answer
1 answer