find the largest number that divides 615 and 963 leaving remainder 6 in each case.

Answer 1

Dear Anamika

To get the largest number (HCF) 1st subtract 6 from 615 and 963
615 - 6 = 609
963 - 6 = 957
Using fundamental theorem
609=3×3×29
957=3×11×29
=》HCF=3×29=87
Therefore, the largest number that divides 615 and 963 leaving remainder 6 in each case is 87.

Hope it is helpful... :-)

Answer 2

Find the greatest number 6 digit exactly divisible by 24, 15, and 36

Answer 3

Very very helpful😘😘

Answer 4

Express the HCF of 468 and 222 as 468x+222y where x,y are integers in two different ways.

Answer 5

Lagest number that divides 1206 and 321 leaving remainder 6.