Find the inverses of the following functions.

Question

y = 3(x - 1)^2, x >= 1

Work:

x = 3(y - 1)^2
x = 3(y - 1)(y - 1)
x = 3(y^2 - y - y + 1)
x = 3y^2 - 6y + 3

And now what do I do!? Please explain and show me how to solve this inverse function!

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Thank you

Answer 1

x = 3(y - 1)^2 would be the inverse but you forgot the second part, y>=1