p(r) or p = 2r2 + 2r - 1
p = 2(r+0.5)2 - 1.5
r = 2(p+0.5)2 - 1.5
(r+1.5)/2 = (p+0.5)2
+-sqrt[(r+1.5)/2] = p + 0.5
p-1(r) = -0.5 +- sqrt[(r+1.5)/2]
After testing, only right-hand side works. Hence p-1(r) = -0.5 + sqrt[(r+1.5)/2]
Find the inverses of each of the functions below algebraically.
p(r)=2r^2+2r−1
3y+5x=18
3 answers
can you find the other one aswell please
Virtual high school right?