y=ln(8-x)
e^y = 8-x
x = 8-e^y
so, f^-1 = 8 - e^x
ln(u) is defined only for u>0, so that means the domain of F is all reals such that 8-x > 0, or x<8.
ln(8-x) has a vertical asymptote where 8-x=0, or x=8.
range is all reals.
domain and range are swapped for the inverse.
Find the inverse of the following function. Find the domain, range, and asymptotes of each function. Graph both functions on the same coordinate plane.
F(x)= ln(8-x)
I am totally lost, somebody please help????
1 answer