original:
y = ln(x+1) + 1
inverse:
x = ln(y+1) + 1
solving for y .....
x-1 = ln(y+1)
y+1 = e^(x-1 , by definition
y = e^(x-1) - 1 <----- your inverse
find the inverse of the following function. find the domain, range and asymptotes of each.
f(x)=In(x+1)+1
please show work.
1 answer