Find the inverse of g(x)=(1/3x)-7 and then find its domain and range.

I already found the inverse of the function.

1 answer

y + 7 = 1 / 3x
reverse x and y
x + 7 = 1/3y
3y = 1/(x+7)
y = 1/(3x+21) that is what I get for inverse.
domain is all real numbers EXCEPT x = -7
range is all real numbers (look at it going to zero at x big - and at x big + and to - and + infinity as x approaches -7
Similar Questions
  1. range of f(x)= 5^(2x^2-1)^(1/2)i know that the domain of the inverse would be the range of this and i've found the inverse but
    1. answers icon 1 answer
  2. The question(s) are as follows:Given: f(x) = 3cos(3x+π) - 4 Find: a) the inverse of F(x) b) the domain and range of F(x) c) the
    1. answers icon 0 answers
  3. Ok I got another one I can figure outThe one-to-one function f is defined by f(x)=(4x-1)/(x+7). Find f^-1, the inverse of f.
    1. answers icon 2 answers
    1. answers icon 1 answer
more similar questions