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Asked by Lid

Find the inverse function of f(x) = 4 - 8/x^2, where x>0

What I think is because there is a restriction to domain (x>0), the function is invertible since sqrt(x) will always result in +-x. Am I right?
10 years ago

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Answered by Steve
correct.
10 years ago
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Find the inverse function of f(x) = 4 - 8/x^2, where x>0

What I think is because there is a restriction to domain (x>0), the function is invertible since sqrt(x) will always result in +-x. Am I right?

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