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Find the inverse function in slope-intercept form (mx+b): f, of, x, equals, minus, 2, x, minus, 10 f(x)= −2x−10Asked by moo
Find the inverse function in slope-intercept form (mx+b):
f, of, x, equals, minus, 2, x, plus, 2
f(x)=
−2x+2
f, of, x, equals, minus, 2, x, plus, 2
f(x)=
−2x+2
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Answered by
GPT-4o mini
To find the inverse function, \( f^{-1}(x) \), of the function \( f(x) = -2x + 2 \), we will follow these steps:
1. Start by replacing \( f(x) \) with \( y \):
\[
y = -2x + 2
\]
2. Swap \( x \) and \( y \) to find the inverse:
\[
x = -2y + 2
\]
3. Now, solve for \( y \):
- First, subtract 2 from both sides:
\[
x - 2 = -2y
\]
- Next, divide both sides by -2:
\[
y = \frac{-(x - 2)}{2} = -\frac{1}{2}x + 1
\]
4. Replace \( y \) with \( f^{-1}(x) \):
\[
f^{-1}(x) = -\frac{1}{2}x + 1
\]
Thus, the inverse function in slope-intercept form is:
\[
f^{-1}(x) = -\frac{1}{2}x + 1
\]
1. Start by replacing \( f(x) \) with \( y \):
\[
y = -2x + 2
\]
2. Swap \( x \) and \( y \) to find the inverse:
\[
x = -2y + 2
\]
3. Now, solve for \( y \):
- First, subtract 2 from both sides:
\[
x - 2 = -2y
\]
- Next, divide both sides by -2:
\[
y = \frac{-(x - 2)}{2} = -\frac{1}{2}x + 1
\]
4. Replace \( y \) with \( f^{-1}(x) \):
\[
f^{-1}(x) = -\frac{1}{2}x + 1
\]
Thus, the inverse function in slope-intercept form is:
\[
f^{-1}(x) = -\frac{1}{2}x + 1
\]
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