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Original Question
Find the inverse function in slope-intercept form (mx+b): f, of, x, equals, minus, 2, x, plus, 2 f(x)= −2x+2 Answer f, to the p...Asked by d
Find the inverse function in slope-intercept form (mx+b):
f, of, x, equals, 5, x, plus, 10
f(x)=
5x+10
Answer
f, to the power minus 1 , left parenthesis, x, right parenthesis, equalsf
−1
(x)
f, of, x, equals, 5, x, plus, 10
f(x)=
5x+10
Answer
f, to the power minus 1 , left parenthesis, x, right parenthesis, equalsf
−1
(x)
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the inverse function \( f^{-1}(x) \) of the function \( f(x) = 5x + 10 \), follow these steps:
1. Replace \( f(x) \) with \( y \):
\[
y = 5x + 10
\]
2. Swap \( x \) and \( y \) to find the inverse:
\[
x = 5y + 10
\]
3. Solve for \( y \):
- Subtract 10 from both sides:
\[
x - 10 = 5y
\]
- Divide both sides by 5:
\[
y = \frac{x - 10}{5}
\]
4. Write the inverse function:
\[
f^{-1}(x) = \frac{x - 10}{5}
\]
Now, let's express it in slope-intercept form \( mx + b \):
\[
f^{-1}(x) = \frac{1}{5}x - 2
\]
So the final answer is:
\[
f^{-1}(x) = \frac{1}{5}x - 2
\]
1. Replace \( f(x) \) with \( y \):
\[
y = 5x + 10
\]
2. Swap \( x \) and \( y \) to find the inverse:
\[
x = 5y + 10
\]
3. Solve for \( y \):
- Subtract 10 from both sides:
\[
x - 10 = 5y
\]
- Divide both sides by 5:
\[
y = \frac{x - 10}{5}
\]
4. Write the inverse function:
\[
f^{-1}(x) = \frac{x - 10}{5}
\]
Now, let's express it in slope-intercept form \( mx + b \):
\[
f^{-1}(x) = \frac{1}{5}x - 2
\]
So the final answer is:
\[
f^{-1}(x) = \frac{1}{5}x - 2
\]
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