almost. You forgot the chain rule:
∫(2x)^n/n^2 = (2x)^(n+1)/(n^2 * (n+1)*2)
FInd the integral of the infinite series of (2x)^n / n^2
I got (2x)^(n+1) / 2n^2(n+1)
is this right
∫ from 0 to ∞ ∑ (2x)^n / n^2
4 answers
That's literally what i had
You are correct, but we were both wrong. It should have been
(2x)^(n+1)/(n^2 * (n+1)) * 2
(2x)^(n+1)/(n^2 * (n+1)) * 2
why that way
0 answers